18x^2=12-4x

Solution for 18x^2=12-4x equation:

18x^2=12-4x

We move all terms to the left:

18x^2-(12-4x)=0

We add all the numbers together, and all the variables

18x^2-(-4x+12)=0

We get rid of parentheses

18x^2+4x-12=0

a = 18; b = 4; c = -12;
Δ = b2-4ac
Δ = 42-4·18·(-12)
Δ = 880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{880}=\sqrt{16*55}=\sqrt{16}*\sqrt{55}=4\sqrt{55}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{55}}{2*18}=\frac{-4-4\sqrt{55}}{36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{55}}{2*18}=\frac{-4+4\sqrt{55}}{36}
$